101 Factorial — What is 101! ?

101! — Results
Exact value  = 
9.4259477 × 10159Show full value
9425947759838359420851623124482936749562312794702543768327889353416977599316221476503087861591808346911623490003549599583369706302603264000000000000000000000000
Number of digits  =  160
Scientific notation  =  9.4259477 × 10159
Stirling's approximation  ≈  9.418174 × 10159
n! ≈ √(2πn) · (n/e)ⁿ

Factorial neighbourhood of 101

The table below shows how quickly factorials grow around 101.

n n! Digits × factor
99 9.3326215 × 10155 156 × 99
100 9.3326215 × 10157 158 × 100
101 9.4259477 × 10159 160 × 101
102 9.6144667 × 10161 162 × 102
103 9.9029007 × 10163 164 × 103

Calculate another factorial

Try: 0 · 5 · 10 · 20 · 52 · 100 · 170

Integers from 0 to 170 (171! overflows IEEE 754 double).


About 101!

101! equals 101 × 100! = 101 × 9.3326215 × 10157. In combinatorics, 101! is the number of ways to arrange 101 distinct objects in a sequence — that is, the number of permutations of a set of 101 elements.

Connections to other branches of mathematics

Like all factorials, 101! appears in the binomial coefficient C(101, k) = 101! / (k! · (101−k)!) for any 0 ≤ k ≤ 101. This counts the number of k-element subsets of a 101-element set. The row 101 of Pascal's triangle sums to 2101 = 1,073,741,824….


About factorials

What is a factorial?

The factorial of a non-negative integer n, written n!, is the product of all positive integers from 1 to n. For example, 5! = 5 × 4 × 3 × 2 × 1 = 120. By convention, 0! = 1 (the empty product).

How fast do factorials grow?

Factorials grow faster than any exponential function. While 2ⁿ doubles at each step, n! multiplies by n — an ever-increasing factor. By n = 100, we already have 100! ≈ 9.33 × 10157, and 170! reaches about 7.26 × 10306.

What is Stirling's approximation?

Stirling's formula provides a practical way to estimate large factorials: n! ≈ √(2πn) · (n/e)ⁿ. The relative error is already below 1% for n = 10 and below 0.1% for n = 100. It is widely used in combinatorics, statistical mechanics, and information theory.

Factorials in combinatorics

Factorials count permutations: n! is the number of ways to arrange n distinct objects in a row. They also appear in combinations C(n,k) = n! / (k!(n−k)!), in Taylor series (the n-th term is divided by n!), and in the Gamma function: Γ(n+1) = n!.

Why does 171! overflow?

IEEE 754 double-precision floats can represent values up to ≈ 1.8 × 10308. Since 170! ≈ 7.26 × 10306 is within range but 171! ≈ 1.24 × 10309 is not, 171! evaluates to Infinity in most languages using native floats.

Frequently asked questions

0! = 1 by convention. This follows from the definition of the empty product: the product of no numbers is the multiplicative identity, 1. It also ensures that C(n,0) = n!/(0!·n!) = 1 remains consistent for all n.
100! has exactly 158 digits. This is computed as ⌊log₁₀(100!)⌋ + 1 = ⌊∑ log₁₀(k) for k=1 to 100⌋ + 1 = 157 + 1 = 158.
Exactly 52! ≈ 8.07 × 1067 ways. This number is so astronomically large that every shuffle performed in all of human history is almost certainly unique.
This tool computes exact integer values up to 170! — the largest factorial that fits in an IEEE 754 double. 170! has 307 digits.
The digit count is ⌊log₁₀(n!)⌋ + 1. By logarithm properties, log₁₀(n!) = ∑ log₁₀(k) for k=1 to n. This is computable in O(n) without big-integer arithmetic.
The Gamma function Γ(z) generalises factorials to complex numbers: Γ(n+1) = n! for any non-negative integer n. Γ(1/2) = √π, and Γ(3/2) = √π/2.


Send your feedback