53 Factorial — What is 53! ?

53! — Results
Exact value  = 
4.2748832 × 1069Show full value
4274883284060025564298013753389399649690343788366813724672000000000000
Number of digits  =  70
Scientific notation  =  4.2748832 × 1069
Stirling's approximation  ≈  4.268167 × 1069
n! ≈ √(2πn) · (n/e)ⁿ

Factorial neighbourhood of 53

The table below shows how quickly factorials grow around 53.

n n! Digits × factor
51 1.5511187 × 1066 67 × 51
52 8.0658175 × 1067 68 × 52
53 4.2748832 × 1069 70 × 53
54 2.3084369 × 1071 72 × 54
55 1.2696403 × 1073 74 × 55

Calculate another factorial

Try: 0 · 5 · 10 · 20 · 52 · 100 · 170

Integers from 0 to 170 (171! overflows IEEE 754 double).


About 53!

53! equals 53 × 52! = 53 × 8.0658175 × 1067. In combinatorics, 53! is the number of ways to arrange 53 distinct objects in a sequence — that is, the number of permutations of a set of 53 elements.

Connections to other branches of mathematics

Like all factorials, 53! appears in the binomial coefficient C(53, k) = 53! / (k! · (53−k)!) for any 0 ≤ k ≤ 53. This counts the number of k-element subsets of a 53-element set. The row 53 of Pascal's triangle sums to 253 = 1,073,741,824….


About factorials

What is a factorial?

The factorial of a non-negative integer n, written n!, is the product of all positive integers from 1 to n. For example, 5! = 5 × 4 × 3 × 2 × 1 = 120. By convention, 0! = 1 (the empty product).

How fast do factorials grow?

Factorials grow faster than any exponential function. While 2ⁿ doubles at each step, n! multiplies by n — an ever-increasing factor. By n = 100, we already have 100! ≈ 9.33 × 10157, and 170! reaches about 7.26 × 10306.

What is Stirling's approximation?

Stirling's formula provides a practical way to estimate large factorials: n! ≈ √(2πn) · (n/e)ⁿ. The relative error is already below 1% for n = 10 and below 0.1% for n = 100. It is widely used in combinatorics, statistical mechanics, and information theory.

Factorials in combinatorics

Factorials count permutations: n! is the number of ways to arrange n distinct objects in a row. They also appear in combinations C(n,k) = n! / (k!(n−k)!), in Taylor series (the n-th term is divided by n!), and in the Gamma function: Γ(n+1) = n!.

Why does 171! overflow?

IEEE 754 double-precision floats can represent values up to ≈ 1.8 × 10308. Since 170! ≈ 7.26 × 10306 is within range but 171! ≈ 1.24 × 10309 is not, 171! evaluates to Infinity in most languages using native floats.

Frequently asked questions

0! = 1 by convention. This follows from the definition of the empty product: the product of no numbers is the multiplicative identity, 1. It also ensures that C(n,0) = n!/(0!·n!) = 1 remains consistent for all n.
100! has exactly 158 digits. This is computed as ⌊log₁₀(100!)⌋ + 1 = ⌊∑ log₁₀(k) for k=1 to 100⌋ + 1 = 157 + 1 = 158.
Exactly 52! ≈ 8.07 × 1067 ways. This number is so astronomically large that every shuffle performed in all of human history is almost certainly unique.
This tool computes exact integer values up to 170! — the largest factorial that fits in an IEEE 754 double. 170! has 307 digits.
The digit count is ⌊log₁₀(n!)⌋ + 1. By logarithm properties, log₁₀(n!) = ∑ log₁₀(k) for k=1 to n. This is computable in O(n) without big-integer arithmetic.
The Gamma function Γ(z) generalises factorials to complex numbers: Γ(n+1) = n! for any non-negative integer n. Γ(1/2) = √π, and Γ(3/2) = √π/2.


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