93 Factorial — What is 93! ?

93! — Results
Exact value  = 
1.1567725 × 10144Show full value
1156772507081641574759205162306240436214753229576413535186142281213246807121467315215203289516844845303838996289387078090752000000000000000000000
Number of digits  =  145
Scientific notation  =  1.1567725 × 10144
Stirling's approximation  ≈  1.155736 × 10144
n! ≈ √(2πn) · (n/e)ⁿ

Factorial neighbourhood of 93

The table below shows how quickly factorials grow around 93.

n n! Digits × factor
91 1.3520015 × 10140 141 × 91
92 1.2438414 × 10142 143 × 92
93 1.1567725 × 10144 145 × 93
94 1.0873661 × 10146 147 × 94
95 1.0329978 × 10148 149 × 95

Calculate another factorial

Try: 0 · 5 · 10 · 20 · 52 · 100 · 170

Integers from 0 to 170 (171! overflows IEEE 754 double).


About 93!

93! equals 93 × 92! = 93 × 1.2438414 × 10142. In combinatorics, 93! is the number of ways to arrange 93 distinct objects in a sequence — that is, the number of permutations of a set of 93 elements.

Connections to other branches of mathematics

Like all factorials, 93! appears in the binomial coefficient C(93, k) = 93! / (k! · (93−k)!) for any 0 ≤ k ≤ 93. This counts the number of k-element subsets of a 93-element set. The row 93 of Pascal's triangle sums to 293 = 1,073,741,824….


About factorials

What is a factorial?

The factorial of a non-negative integer n, written n!, is the product of all positive integers from 1 to n. For example, 5! = 5 × 4 × 3 × 2 × 1 = 120. By convention, 0! = 1 (the empty product).

How fast do factorials grow?

Factorials grow faster than any exponential function. While 2ⁿ doubles at each step, n! multiplies by n — an ever-increasing factor. By n = 100, we already have 100! ≈ 9.33 × 10157, and 170! reaches about 7.26 × 10306.

What is Stirling's approximation?

Stirling's formula provides a practical way to estimate large factorials: n! ≈ √(2πn) · (n/e)ⁿ. The relative error is already below 1% for n = 10 and below 0.1% for n = 100. It is widely used in combinatorics, statistical mechanics, and information theory.

Factorials in combinatorics

Factorials count permutations: n! is the number of ways to arrange n distinct objects in a row. They also appear in combinations C(n,k) = n! / (k!(n−k)!), in Taylor series (the n-th term is divided by n!), and in the Gamma function: Γ(n+1) = n!.

Why does 171! overflow?

IEEE 754 double-precision floats can represent values up to ≈ 1.8 × 10308. Since 170! ≈ 7.26 × 10306 is within range but 171! ≈ 1.24 × 10309 is not, 171! evaluates to Infinity in most languages using native floats.

Frequently asked questions

0! = 1 by convention. This follows from the definition of the empty product: the product of no numbers is the multiplicative identity, 1. It also ensures that C(n,0) = n!/(0!·n!) = 1 remains consistent for all n.
100! has exactly 158 digits. This is computed as ⌊log₁₀(100!)⌋ + 1 = ⌊∑ log₁₀(k) for k=1 to 100⌋ + 1 = 157 + 1 = 158.
Exactly 52! ≈ 8.07 × 1067 ways. This number is so astronomically large that every shuffle performed in all of human history is almost certainly unique.
This tool computes exact integer values up to 170! — the largest factorial that fits in an IEEE 754 double. 170! has 307 digits.
The digit count is ⌊log₁₀(n!)⌋ + 1. By logarithm properties, log₁₀(n!) = ∑ log₁₀(k) for k=1 to n. This is computable in O(n) without big-integer arithmetic.
The Gamma function Γ(z) generalises factorials to complex numbers: Γ(n+1) = n! for any non-negative integer n. Γ(1/2) = √π, and Γ(3/2) = √π/2.


Send your feedback